6v^2+8v-8=0

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Solution for 6v^2+8v-8=0 equation: 



6v^2+8v-8=0

a = 6; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·6·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16}{2*6}=\frac{-24}{12}
=-2
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16}{2*6}=\frac{8}{12}
=2/3
$

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